Last character of the textbox is a .(dot) and if yes, replace empty else nothing

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#1
  • I want to show, Check if the last Character of textbox is a .(dot) then that last character consider as empty. else nothing to change.
    Example:
  • if textbox.text = 01234. then result will be =01234
    else if textbox.text = 01234.0 then result will be =01234.0

blocks (1)
blocks (3)

I have tried my best but I am not getting the answer please help.
Thank you

#2

Don’t you want just the (.) dot killed and not a space ( ) instead? Just bc it’s more logic. :thinking:

If no, I am working on your space-replacement-method…

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#3

You set the variable dot to empty string, thats why you got nothing.

1 Like
#4

Yes, but he is also just returning the emptystring and not the whole text + the string. This is his mistake.

1 Like
#5

I have a test currently (yes I took my time out so I could answer this)
Here ya go, it’s completely untested btw so do let me know if there are any bugs
blocks (41)

1 Like
#6

Thats exactly what I want to say lol

#9

I use a clock component for calculation. When the textbox.text is changed it is calculated. The problem is contains a .dot in the text box, which shows the NaN error. Once the decimal place is filled it will work properly.

#11

Pls try what ontstudio give you

Also, an alternative method (but more complicated)

blocks (1)
blocks (1)871Ă—344 24.4 KB

Change the Text_Box1.Text to want you want, or make a input

#12

Thank you so much for your solution. But this is not dealing with my problem.

#13

can u explain why?

#14

Wait what? Why i am the solution

#15

Working well Thank you so much. :heart_eyes:

blocks (4)

blocks (5)
blocks (5)913Ă—394 27.8 KB

1 Like
#16

Oh i tried ontstudio solution but there’s an error
And I know the error
blocks
I used ontstudio idea, and make some modification and it worked
In the “if” part, the segment length cannot be length of text. Instead it should be 1
In the “then” part segment start should be 1

3 Likes
#17

Yeah, I got it. The start should be 1, not length. Silly me. Sorry, I was nervous because the clock on the test was ticking, and I was out here answering questions on the community.

2 Likes
#18

My thanks to everyone.

#19

This is shows false. not working for me.

#20

There’s no way it will

And it worked for me
btw this is the better solution.

1 Like
#21

I tested many times, this is the best solution. Thank you very much. :smiley:

2 Likes
#22

what about using the On Text Changed event of the textbox for this?
Taifun

2 Likes
#23

I will do it. Thanks for your suggestion.

1 Like