Daily Challenge #97

Ansh_Anand · August 28, 2020, 5:27pm

Hello Everyone,
I created a daily challenge before but no one replied. This time on my 100th day on Kodular Community I am creating a new challenge that will be simple & easy.

AIM:
Convert the percentage score into the grading system given below:
Return “A+” if score = 100
Return “A” if 90<= score <100
Return “B” if 80<= score <90
Return “C” if 70<= score <80
Return “D” if 60<= score <70
Return “E” if 50<= score <60
Return “F” if score <50

EXAMPLE:
comp

NOTES:

No extension or component can be used.
No need to take care of unexpected inputs like strings or special character
Shortest & Fastest answer will be marked as solution
Last date/time to post your answer is 2020-08-29T18:30:00Z

PRIZE:

All The BEST

Regards,
Ansh Anand

Ansh_Anand · August 28, 2020, 6:05pm

There is mistake. Don’t worry you have 1 day left

Mohamed_Tamer · August 28, 2020, 10:24pm

That’s my try :
17 blocks including the procedure block ( using dictionaries ):

Blocks

Ansh_Anand · August 29, 2020, 2:15am

Nice One

Target for other Koders :
Do this task now in less than 17 blocks

WatermelonIce · August 29, 2020, 8:28am

Hello, can the score be less than 0 (negative)?

If no,

Solution (12 blocks)

0-100

If yes,

Solution (15 blocks)

blocks (1)

Ansh_Anand · August 29, 2020, 10:11am

Whoa , Great. I have the same code. Perfect. Just omit intialise local block and use list directly to reduce 2 blocks (making it 10).

Also there an imperfect way of reducing two more blocks by removing + 1 block and replacing floor with ceil and 10 with 9.99999 but it will work accurate for scores only upto specific decimal places and give different results for number like 89.999999999. More you increase the 9 after point it will get more accurate.