Open a specific file location by activity starter

[M.H.M (M.H)]

I created an application that converts videos into music, and I want when the user presses a certain button, the location of the file will be opened.
I know an activity starter will be used but I don’t know how to do it

[Still-learning (1-2-3-4...)]

Did you try like this method.

COMPONENT= activity starter
ACTION= android.intent.action.VIEW
DATA URI = file:///(path)

[M.H.M (M.H)]

thanks br0
I will try it

[M.H.M (M.H)]

Unfortunately, it didn’t work. There appears to be a wrong path

[Still-learning (1-2-3-4...)]

Show us what you have tried

[M.H.M (M.H)]

[Still-learning (1-2-3-4...)]

Here before proceeding start activity use one label and try to catch audiopath whether it is giving exact pathway or not… if not then problme is there .

Set label1text to audio extractor audiopath

[M.H.M (M.H)]

I have solved the problem
I forgot to put a colon after the word file
File: /// (path)

[M.H.M (M.H)]

@Still-learning

DATA URI = file///(path)

You did not write it correctly

[Still-learning (1-2-3-4...)]

Oh , while typing in mobile, it missed. Anyway you got it. Correct?

[M.H.M (M.H)]

yes , thanks br0