Search info into .csv file, Modific & Save

Thx u for your help !
Now i have a sunshine !

I try change any blocks… why ? the result is all Row, for example using ID : 12345
-Result name (or label1) = Maximun Prada 1 Blue

Now you can try, select list item to separate each row value and show it in labels.

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jejejeje Im sorry for my bad english:

For the block made for you.
When . Got row put the info to Label1 ( Using index in list thing :12345 ), the result is all Row ( Maximun Prada 1 Blue ) in the Label1.
the correct thing would be just the name ( Maximun Prada )

Label1 = Maximun Prada
Label2 = 1
Label3 = Blue

The result is in list form. You have to select it with respective to the index.

blocks (20)

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Dear Kiran !
really very very Thanks !

It worked fine !!! Monster !

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A post was split to a new topic: How to to filter and display data from spreadsheet?

Dear @The_K_Studio
or Other koders

Please, can you check this error?

image

image

You have set label text to global variable value which is in List form.

As I said previously, whenever there is list and when you want to show it in label then use select list item with index block.

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Dear.
not work for me :sweat:

@The_K_Studio

image

How you want to show your data?

Thx u for answer Mr !

For example:
If text_ID is typed: 12345
so
Nombre: DANNY OCULEN
Condicion: PROPIETARIO
Vehiculo: N/A
Unidad: A1-301

image

Here, set index 2, 3 and 4 instead of 1, 2 and 3.

IMG_20201020_210236

Dear, not work

I think, can be…does not detect the Text_ID

PM me your aia, I will check it.

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Hi Koders

Please !
I try use any blocks…
but, I don’t understand why the data doesn’t return in order.
any idea what the error may be?

image


image

These indexes should be the list number (row number) for which you want to show data in labels.

For eg. To get data of 1st list item (row) set index 1 for all.

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The result is same always!

image

you are not selecting the row with same index u have use same index for getting a complete row