hello every one,
How to create a list in list ???
Can you explain, what you want to do exactly?
@The_K_Studio
x=(2 (3 1))
I want to create an x list, which contains two items
The first item is a number (2) and the second item is a list (3 1 )
Then just use make a list block.
In that first list item will be 2
And second another list which is also make a list block with two list items 3 and 1.
That’s it.
@The_K_Studio
i want to select first item of the inside list
will return error
@The_K_Studio
x1 a1 b1
x4 a4 b4
x3 a3 b3
x2 a2 b2
All I want is to arrange this table based on column x and then choose any of the a or b for the x after arranging it
Show your blocks please. How can we possibly know what you’ve done?
It works for me:
To set the item of the sublist:
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You can use dictionary instead 
Or
Here is a nice example by @Taifun which can help you I think
How to create a nested listpicker
Go through it once 
3 Likes
@The_K_Studio
Thank you it works for me too
Mark the reply as solution, which helped you to solve your query @sherif
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